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Cubes and Cube Roots
6-
Lecture1.1
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Lecture1.2
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Lecture1.3
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Lecture1.4
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Lecture1.5
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Lecture1.6
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Exponents and Powers
10-
Lecture2.1
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Lecture2.2
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Lecture2.3
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Lecture2.4
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Lecture2.5
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Lecture2.6
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Lecture2.7
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Lecture2.8
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Lecture2.9
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Lecture2.10
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Linear Equations in One Variable
5-
Lecture3.1
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Lecture3.2
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Lecture3.3
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Lecture3.4
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Lecture3.5
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Rational Numbers
6-
Lecture4.1
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Lecture4.2
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Lecture4.3
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Lecture4.4
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Lecture4.5
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Lecture4.6
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Direct and Inverse Proportions
4-
Lecture5.1
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Lecture5.2
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Lecture5.3
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Lecture5.4
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Square and Square Roots
5-
Lecture6.1
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Lecture6.2
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Lecture6.3
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Lecture6.4
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Lecture6.5
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Chapter Notes – Cubes and Cube Roots
Cube:
It is a three-dimensional figure made of six equal square sides.
Cube number or Perfect cubes:
It is a number which is the product of three same numbers.
Example: Cube number of 2 will be 2 x 2 x 2 = 8. Thus, 8 is a cube number.
Cubes of some natural numbers:
Number | Cube | Number | Cube |
1 | 1 x 1 x 1 = 1 | 11 | 11 x 11 x 11 = 1331 |
2 | 2 x 2 x 2 = 8 | 12 | 12 x 12 x 12 = 1728 |
3 | 3 x 3 x 3 = 27 | 13 | 13 x 13 x 13 = 2197 |
4 | 4 x 4 x 4 = 64 | 14 | 14 x 14 x 14 = 2744 |
5 | 5 x 5 x 5 = 125 | 15 | 15 x 15 x 15 = 3375 |
6 | 6 x 6 x 6 = 216 | 16 | 16 x 16 x 16 = 4096 |
7 | 7 x 7 x 7 = 343 | 17 | 17 x 17 x 17 = 4913 |
8 | 8 x 8 x 8 = 512 | 18 | 18 x 18 x 18 = 5832 |
9 | 9 x 9 x 9 = 729 | 19 | 19 x 19 x 19 = 6859 |
10 | 10 x 10 x 10 = 1000 | 20 | 20 x 20 x 20 = 8000 |
… | … | … | … |
Properties of Cube Numbers:
1. The cube of an even number will always be an even number.
Example: 83 = 512, 123 = 1728, etc.
2. The cube of odd number will always be an odd number.
Example: 73 = 343, 193 = 6589, etc.
3. If the cube number have x at its one’s digit or unit’s place then it always end with the digit as shown in the table below:
Unit’s digit of number | Last digit of its cube number | Example |
1 | 1 | 113 = 1331, 213 = 9261, etc. |
2 | 8 | 23 = 8, 123 = 1728, 323 = 32768, etc. |
3 | 7 | 133 = 2197, 533 = 148877, etc. |
4 | 4 | 243 = 13824, 743 = 405224, etc. |
5 | 5 | 153 = 3375, 253 = 15625, etc. |
6 | 6 | 63 = 216, 263 = 17576,etc. |
7 | 3 | 173 = 4913, 373 = 50653,etc. |
8 | 2 | 83 = 512, 183 = 5832, etc. |
9 | 9 | 193 = 6859, 393 = 59319, etc. |
10 | 20 | 103 = 1000, 203 = 8000, etc. |
Example 1: Find the one’s digit for 27.
Solution: As the last digit of given number is 7, So the one’s digit for 27’s cube number will be 3.
Example 2: Find the one’s digit for 149.
Solution: As the last digit of given number is 9, So the one’s digit for 149’s cube number will be 9.
Interesting patterns of Cube Number:
1. Addition of consecutive odd numbers will give Cube Number-
13 = 1 = 1
23 = 8 = 3 + 5
33 = 27 = 7 + 9 + 11
43 = 64 = 13 + 15 + 17 + 19
53 = 125 = 21 + 23 + 25 + 27 + 29
2. Cubes and their prime factors-
The prime factors of any cube number will be in pair of 3.
Example:
(i) 43 = 64 = 2 x 2 x 2 x 2 x 2 x 2 = 23 x 23
(ii)123 = 1728 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 = 23 x 23 x 33
Note:
(i) If any prime factor is not in pair of 3, then it will not be a perfect cube.
(ii) Numbers like 1729, 4104, 13832, are known as Hardy – Ramanujan Numbers. They can be expressed as sum of two cubes in two different ways.
Example 1: Is 128 a perfect cube number?
Solution: After finding prime factors of 128, we can write 128 = 2 x 2 x 2 x 2 x 2 x 2 x 2
We can see that each prime factor is not in pair of 3. Hence, 128 is not a perfect cube number.
Example 2: Find the smallest number by which 675 must be multiplied to obtain a perfect cube.
Solution: On finding prime factors of 675, we have 675 = 3 x 3 x 3 x 5 x 5.
We can see that, triplets of 5 is missing. Hence, on multiplying given number by 5 we can have a perfect cube number. Thus, 675 x 5 = 3375 which is a perfect cube number.
Example 3: Find the smallest number by which 192 must be divided to obtain a perfect cube.
Solution: On finding prime factors of 192, we have 192 = 2 x 2 x 2 x 2 x 2 x 2 x 3.
We can see that, triplets of 3 is missing while other numbers have triplets. Hence, on dividing given number by 3 we can have a perfect cube number.
Thus, 192 / 3 = 64 which is a perfect cube number.
Cube Roots:
It is the inverse operation of finding a cube. Symbol ∛ represents a cube-root.
Example: ∛8 = 2, ∛216 = 6, etc.
Methods to find a cube root:
1. Prime factorisation method:
Follow the steps given below to understand this method:
Step 1: Find all the prime factors of given cube number.
Step 2: Make as many group of 3 for all common digit.
Step 3: Replace group of 3 by respective single digit.
Step 4: Product of these single digits will give the cube root.
Example 1: Find cube root of 3375.
Solution:
Step 1: Find all the prime factors of given cube number.
The prime factors of 3375 will be 5, 5, 3, 3, 3, 5.
Step 2: Making group of 3 for every common digit.
Here, we get (3 x 3 x 3) and (5 x 5 x 5)
Step 3: Replacing group of 3 by respective digit.
Thus, we get 3 and 5.
Step 4: Taking product of digits.
We get, 3 x 5 = 15.
Thus, ∛3375 = 15.
Example 2: Find cube root of 46656.
Solution: The prime factors of 46656 are 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3.
On grouping, we have 46656 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3.
So, ∛46656 = 2 x 2 x 3 x 3 = 36.
2. Estimation Method:
Follow the steps given below to understand this method:
Step 1: For given cube number start making groups of three digits starting from the right most digit of the number. We can estimate the cube root of a given cube number through a step by step process.
Step 2: First group will give you the one’s (or unit’s) digit of the required cube root.
Step 3: Now take another group, let it be xyz. Find, a3 < xyz < b3. We take the one’s place, of the smaller number a3 as the ten’s place of the required cube root.
Step 4: The digits obtained in step 2 and step 3 will give the final result.
Example 1: Find the cube root of 17576.
Solution:
Step 1: We will form groups of three starting from the rightmost side of 17567.
Thus, the two groups formed will be 576 and 17.
Step 2: For the group 576, the number at unit’s place will be 6.
Step 3: The other group is 17. The group 17 lies between 23 and 33. Now, as per the method we will take the smaller number which is 2 in this case.
Step 4: Combining the two digits obtained in step 2 and 3, we get 26.
Thus, ∛17576 = 26.
Example 2: Guess the cube root of 4913.
Solution:The two groups of 4913 will be 4 and 913.
For group 913, as the last digit is 3 so its cube root will have 7 at its unit place.
For group 4, it will lie between 13 < 4 < 23. Taking the smaller number which is 1 in this case.
Thus, ∛4913 = 17.